Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.4 Solving Quadratic Equations by the Square Root Property and Completing the Square - 4.4 Exercises - Page 349: 69

Answer

$c(p) = \frac{2}{7}\left(p-\frac{35}{4} \right)^2-\frac{1249}{56}$

Work Step by Step

The conversion of the function to the standard vertex form is self explanatory. All mathematical steps are shown below. $$ \begin{aligned} c(p)&=\frac{2}{7} p^2-5 p-\frac{3}{7}\\ & = \frac{2}{7}\left( p^2-\frac{7}{2}\cdot 5p \right) -\frac{3}{7}\\ &= \frac{2}{7}\left( p^2-\frac{35}{2}\right) -\frac{3}{7}\\ & = \frac{2}{7}\left[ p^2-\frac{35}{2}p+\left( \frac{35}{4}\right)^2\right]-\frac{3}{7}-\frac{2}{7}\cdot \left( \frac{35}{4}\right)^2\\ & = \frac{2}{7}\left(p-\frac{35}{4} \right)^2-\frac{3}{7}-\frac{2\cdot 1225}{7\cdot 16} \\ & = \frac{2}{7}\left(p-\frac{35}{4} \right)^2-\frac{3}{7}\cdot\frac{8}{8}-\frac{175}{ 8}\cdot \frac{7}{7}\\ & = \frac{2}{7}\left(p-\frac{35}{4} \right)^2-\frac{1249}{56}. \end{aligned} $$
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