Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 531: 25

Answer

$x=\{ 1,125 \}$

Work Step by Step

Let $z=x^{1/3}$. Then the given expression, $ x^{2/3}-6x^{1/3}+5=0 ,$ is equivalent to \begin{array}{l}\require{cancel} z^2-6z+5=0 \\\\ (z-5)(z-1)=0 \\\\ z=\{1,5\} .\end{array} Since $z=x^{1/3}$, then if $z=1$, \begin{array}{l}\require{cancel} 1=x^{\frac{1}{3}} \\\\ (1)^3=(x^{\frac{1}{3}})^3 \\\\ 1=x .\end{array} Since $z=x^{1/3}$, then if $z=5$, \begin{array}{l}\require{cancel} 5=x^{\frac{1}{3}} \\\\ (5)^3=(x^{\frac{1}{3}})^3 \\\\ 125=x .\end{array} Hence, $ x=\{ 1,125 \} .$
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