Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 531: 16

Answer

$x=\dfrac{1\pm i\sqrt{35}}{9}$

Work Step by Step

Using the properties of equality, the given quadratic equation, $ 9x^2+4=2x ,$ is equivalent to \begin{array}{l}\require{cancel} 9x^2-2x+4=0 .\end{array} Using $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$ or the Quadratic Formula, the solutions of the quadratic equation above are \begin{array}{l}\require{cancel} x=\dfrac{-(-2)\pm\sqrt{(-2)^2-4(9)(4)}}{2(9)} \\\\ x=\dfrac{2\pm\sqrt{4-144}}{18} \\\\ x=\dfrac{2\pm\sqrt{-140}}{18} \\\\ x=\dfrac{2\pm\sqrt{-1}\cdot\sqrt{140}}{18} \\\\ x=\dfrac{2\pm i\sqrt{4\cdot35}}{18} \\\\ x=\dfrac{2\pm i\sqrt{(2)62\cdot35}}{18} \\\\ x=\dfrac{2\pm 2i\sqrt{35}}{18} \\\\ x=\dfrac{2(1\pm i\sqrt{35})}{18} \\\\ x=\dfrac{\cancel{2}(1\pm i\sqrt{35})}{\cancel{2}(9)} \\\\ x=\dfrac{1\pm i\sqrt{35}}{9} .\end{array}
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