Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 531: 6

Answer

$75\sqrt2$ miles, 106.1 miles

Work Step by Step

$x=$ distance of one ship $x^2+x^2=150^2$ $2x^2=22500$ $2x^2/2=22500/2$ $x^2=11250$ $\sqrt {x^2} = \sqrt{11250}$ $x = ± \sqrt {2*5625}$ $x = ± \sqrt {2*75*75}$ $x = ± 75 \sqrt 2$ We are looking for a distance, so we use the positive square root of 2. $x= 75 \sqrt 2$ $\sqrt 2 = 1.414$ $75*1.414 = 106.066$ $106.066$ $106.1$
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