Answer
$a=-\frac{6}{7}$ and $a=5$
Work Step by Step
$7a^{2}=29a+30$
$7a^{2}-29a-30=0$
$7a^{2}+6a-35a-30=0$
$a(7a+6)-5(7a+6)=0$
$(7a+6)(a-5)=0$
$(7a+6)=0$ and $(a-5)=0$
$a=-\frac{6}{7}$ and $a=5$
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