Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 531: 2

Answer

$a=-\frac{6}{7}$ and $a=5$

Work Step by Step

$7a^{2}=29a+30$ $7a^{2}-29a-30=0$ $7a^{2}+6a-35a-30=0$ $a(7a+6)-5(7a+6)=0$ $(7a+6)(a-5)=0$ $(7a+6)=0$ and $(a-5)=0$ $a=-\frac{6}{7}$ and $a=5$
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