Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 531: 23

Answer

$x=\left\{ \dfrac{2}{3},5 \right\}$

Work Step by Step

Multiplying both sides by the $LCD= x(x-2) ,$ the solution/s to the given equation, $ \dfrac{5}{x}+\dfrac{6}{x-2}=3 ,$ is/are \begin{array}{l}\require{cancel} (x-2)(5)+x(6)=x(x-2)(3) \\\\ 5x-10+6x=3x^2-6x \\\\ 0=3x^2+(-6x-6x-5x)+10 \\\\ 3x^2-17x+10=0 \\\\ (3x-2)(x-5)=0 \\\\ x=\left\{ \dfrac{2}{3},5 \right\} .\end{array}
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