Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 531: 24

Answer

$x=\{ \pm5,\pm2i\}$

Work Step by Step

Using factoring and then equating each factor to $0$, the solutions of the given quadratic equation, $ x^4-21x^2-100=0 ,$ are \begin{array}{l}\require{cancel} (x^2-25)(x^2+4)=0 \\\\ x^2-25=0 \\\\ x^2=25 \\\\ x=\pm\sqrt{25} \\\\ x=\pm5 ,\\\\\text{OR}\\\\ x^2+4=0 \\\\ x^2=-4 \\\\ x=\pm\sqrt{-4} \\\\ x=\pm\sqrt{-1}\cdot\sqrt{4} \\\\ x=\pm i\cdot2 \\\\ x=\pm 2i .\end{array} Hence, $ x=\{ \pm5,\pm2i\} $.
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