Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 531: 20

Answer

$6+6\sqrt 2$ cm

Work Step by Step

$x^2+x^2=(6+x)^2$ $2x^2=(6+x)(6+x)$ $2x^2=6*6+6*x+x*6+x*x$ $2x^2=36+12x+x^2$ $2x^2=x^2+12x+36$ $2x^2-2x^2= x^2+12x+36-2x^2$ $0=-x^2+12x+36$ $0*-1=-1(-x^2+12x+36)$ $0=x^2-12x-36$ $0+36=x^2-12x-36+36$ $36=x^2-12x$ $36+(-12/2)^2=x^2-12x+(-12/2)^2$ $36+(-6)^2=x^2-12x+(-6)^2$ $36+36=x^2-12x+36$ $72=(x-6)^2$ $\sqrt {72}=\sqrt {(x-6)^2}$ $±6\sqrt 2=(x-6)$ We can’t have a negative length, so we ignore the negative value. $±6\sqrt 2=(x-6)$ $6\sqrt 2=x-6$ $6+6\sqrt 2=x-6+6$ $6+6\sqrt 2=x$
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