Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 531: 3

Answer

$m=\pm7$

Work Step by Step

Step 1: $4m^{2}=196$ Step 2: $(2m)^{2}=196$ Step 3: $\sqrt {(2m)^{2}}=\sqrt {196}$ Step 4: $2m=\pm14$ Step 5: $m=\pm7$
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