Answer
$12-16i$
Work Step by Step
Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the expression $
4(2-i)^2
$ simplifies to
\begin{array}{l}
4[(2)^2+2(2)(-i)+(-i)^2]
\\=
4[4-4i+i^2]
\\=
4[4-4i+(-1)]
\\=
4[3-4i]
\\=
12-16i
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 463: 79
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