Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 463: 20

Answer

$-2\sqrt 3$

Work Step by Step

$\sqrt -2 \times \sqrt -6=\sqrt (4\times-1\times-1\times3)=\sqrt 4\times\sqrt -1\times\sqrt -1\times\sqrt 3=2\times i\times i\times\sqrt 3=2\times i^{2}\times\sqrt 3=-2\sqrt 3$ We know that $\sqrt -1=i$ and that $i^{2}=-1$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.