Answer
$i\sqrt 4.9$
Work Step by Step
$\frac{\sqrt (49)}{\sqrt (-10)}=\sqrt (-\frac{49}{10})=\sqrt (-4.9)=\sqrt (-1\times4.9)=\sqrt -1\times\sqrt 4.9=i\sqrt 4.9$
We know that $\sqrt -1=i$, because $i^{2}=-1$.
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