Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 13


$24i\sqrt 7$

Work Step by Step

$8\sqrt(-63)=8\sqrt(9\times-1\times7)=8(\sqrt 9\times\sqrt -1\times\sqrt 7)=8(3i\sqrt 7)=24i\sqrt 7$ We know that $\sqrt -1=i$, because $i^{2}=-1$.
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