Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 463: 42

Answer

$-\dfrac{5i}{6}$

Work Step by Step

The expression $ \dfrac{5}{6i} $ simplifies to \begin{array}{l} \dfrac{5}{6i} \cdot \dfrac{6i}{6i} \\\\= \dfrac{30i}{36i^2} \\\\= \dfrac{30i}{36(-1)} \\\\= -\dfrac{30i}{36} \\\\= -\dfrac{5i}{6} .\end{array}
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