Answer
$\dfrac{-15i+16i}{3}$
Work Step by Step
Using $i^2=-1$, the expression $
\dfrac{16+15i}{-3i}
$ simplifies to
\begin{array}{l}
\dfrac{16+15i}{-3i}
\cdot
\dfrac{3i}{3i}
\\\\=
\dfrac{48i+45i^2}{-9i^2}
\\\\=
\dfrac{48i+45(-1)}{-9(-1)}
\\\\=
\dfrac{-45i+48i}{9}
\text{(divide all terms by 3)}
\\\\=
\dfrac{-15i+16i}{3}
.\end{array}
