Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 22



Work Step by Step

$\sqrt 3\times\sqrt (-27)=\sqrt (3\times-27)=\sqrt (-81)=\sqrt (81\times-1)=\sqrt 81\times\sqrt -1=9i$ We know that $\sqrt81=9$, because $9^{2}=81$. We also know that $\sqrt -1=i$, because $i^{2}=-1$.
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