Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 463: 67

Answer

$17+144i$

Work Step by Step

Using $i^2=-1$ and $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the expression $ (9+8i)^2 $ is equivalent to \begin{array}{l} (9)^2+2(9)(8i)+(8i)^2 \\= 81+144i+64i^2 \\= 81+144i+64(-1) \\= 17+144i .\end{array}
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