Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 463: 54

Answer

$5+10i$

Work Step by Step

Using $i^2=-1$, the expression $ -5i(-2+i) $ simplifies to \begin{array}{l} 10i-5i^2 \\= 10i-5(-1) \\= 5+10i .\end{array}
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