Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 463: 14

Answer

$8i\sqrt 5$

Work Step by Step

$4\sqrt(-20)=4\sqrt(4\times-1\times5)=4(\sqrt 4\times\sqrt -1\times\sqrt 5)=4(2i\sqrt 5)=8i\sqrt 5$ We know that $\sqrt -1=i$, because $i^{2}=-1$.
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