Answer
$(\frac{3}{2},-6)$
Work Step by Step
We know that the midpoint of the line segment whose endpoints are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is the point with coordinates $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$.
Therefore, a line with endpoints (-3, -4) and (6, -8) will have a midpoint of $(\frac{-3+6}{2},\frac{-4+(-8)}{2})=(\frac{3}{2},\frac{-12}{2})=(\frac{3}{2},-6)$.
