## Intermediate Algebra (6th Edition)

$2xy^{2} \sqrt[5]( x)^{2}$
$\frac{\sqrt[5] 64x^{10}y^{3}}{\sqrt[5] 2x^{3}y^{-7}}$ Using the product and quotient rules for exponents and radicals $= \sqrt[5] \frac{64x^{10}y^{3}}{2x^{3}y^{-7}}$ $= \sqrt[5](32 x^{10-3}. y^{3-(-7)})$ $= \sqrt[5]32 x^{7}. y^{10}$ $= \sqrt[5](2^{5}. x^{7}. y^{10})$ $=(2^{5}. x^{7}. y^{10})^{\frac{1}{5}}$ $=(2^{5}. x^{5}.x^{2}. y^{10})^{\frac{1}{5}}$ $=2xy^{2} \sqrt[5]( x^{2})$