## Intermediate Algebra (6th Edition)

The quotient rule states that $\frac{\sqrt[n] a}{\sqrt[n] b}=\sqrt[n] (\frac{a}{b})$ (where $\sqrt[n] a$ and $\sqrt[n] b$ are real numbers and $\sqrt[n] b$ is nonzero). Therefore, $\frac{\sqrt[3] 12}{\sqrt[3] 4}=\sqrt[3] 8$ is a false statement. The correct statement is $\frac{\sqrt[3] 12}{\sqrt[3] 4}=\sqrt[3] \frac{12}{4}=\sqrt[3] 3$.