Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set - Page 433: 45


$y^{2}\sqrt y$

Work Step by Step

$\sqrt (y^{5})=\sqrt (y^{4}\times y)=\sqrt (y^{4})\times\sqrt y=y^{2}\sqrt y$ We know that $\sqrt (y^{4})=y^{2}$, because $(y^{2})^{2}=y^{2\times2}=y^{4}$.
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