Answer
$\sqrt 5\approx2.236$ units
Work Step by Step
We know that the distance $d$ between two points $(x_{1},y_{1})$ and $x_{2},y_{2})$ is given by $d=\sqrt ((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2})$.
Therefore, the distance between $(0,-\sqrt 2)$ and $(-\sqrt 3,0)$ will be $d=\sqrt ((-\sqrt 3-0))^{2}+(0-(-\sqrt 2))^{2})=\sqrt ((-\sqrt 3)^{2}+(\sqrt 2)^{2})=\sqrt (3+2)=\sqrt 5\approx2.236$ units