Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set - Page 433: 54


$-2b^{3}\sqrt (5a)$

Work Step by Step

$-\sqrt (20ab^{6})=-\sqrt (4\times 5a\times b^{6})=-(\sqrt 4\times \sqrt (5a)\times \sqrt (b^{6}))=-(2b^{3}\sqrt (5a))=-2b^{3}\sqrt (5a)$ We know that $\sqrt 4=2$, because $2^{2}=4$. We also know that $\sqrt (b^{6})=b^{3}$, because $(b^{3})^{2}=b^{3\times2}=b^{6}$
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