Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set - Page 433: 33

Answer

$4\sqrt [3] 3$

Work Step by Step

$\sqrt [3] 192=\sqrt [3] 64\times\sqrt [3] 3=4\sqrt [3] 3$ We know that $\sqrt[3] 64=4$, because $4^{3}=64$.
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