Answer
$(4,-2)$
Work Step by Step
We know that the midpoint of the line segment whose endpoints are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is the point with coordinates $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$.
Therefore, a line with endpoints (6, -8) and (2, 4) will have a midpoint of $(\frac{6+2}{2},\frac{-8+4}{2})=(\frac{8}{2},\frac{-4}{2})=(4,-2)$.
