Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set - Page 433: 40


$8y^{4}\sqrt y$

Work Step by Step

$\sqrt (64y^{9})=\sqrt (64y^{8}\times y)=\sqrt (64y^{8})\times\sqrt y=8y^{4}\sqrt y$ We know that $\sqrt (64y^{8})=8y^{4}$, because $(8y^{4})^{2}=(8\times8)\times y^{4+4}=64y^{8}$.
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