Answer
$4x^{2}+4x+1$
Work Step by Step
We are given the expression $(2x+1)^{2}$, which is equivalent to $(2x+1)(2x+1)$. We can use the FOIL method to simplify.
F=$2x\times 2x=4x^{2}$
O= $2x\times1=2x$
I=$1\times 2x=2x$
L=$1\times1=1$
Now, we can add these terms together.
$(2x+1)^{2}=(4x^{2})+(2x)+(2x)+(1)=4x^{2}+4x+1$
