Answer
$\left\{
7,4,1,-2,-5
\right\}
$
Work Step by Step
With $a_1=7$ and $d=-3$, then
\begin{array}{l}
a_{1}=7
,\\\\
a_2=7+(-3)\\
a_2=4
,\\\\
a_3=4+(-3)\\
a_3=1
,\\\\
a_4=1+(-3)\\
a_4=-2
,\\\\
a_5=-2+(-3)\\
a_5=-5
.\end{array}
Hence, the first 5 terms are $
\left\{
7,4,1,-2,-5
\right\}
$
