Answer
$-10$
Work Step by Step
Given $
a_n=n(n-4)
$, the first 3 terms are
\begin{array}{l}
a_1=1(1-4)\\
a_1=-3
,\\\\
a_2=2(2-4)\\
a_2=2(-2)\\
a_2=-4
,\\\\
a_3=3(3-4)\\
a_3=3(-1)\\
a_3=-3
\end{array}
Hence, the sum is $
-3-4-3
=
-10
.$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 11 - Sections 11.1-11.3 - Integrated Review - Sequences and Series - Page 653: 23
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