Answer
$a_{20}=185$
Work Step by Step
Using $a_n=a_1+(n-1)d$, then
\begin{array}{l}
a_{20}=-100+(20-1)(15)\\
a_{20}=-100+285\\
a_{20}=185
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 11 - Sections 11.1-11.3 - Integrated Review - Sequences and Series - Page 653: 16
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