Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Sections 11.1-11.3 - Integrated Review - Sequences and Series - Page 653: 3

Answer

$\left\{ 1,3,9,27,81 \right\} $

Work Step by Step

Given that $ a_n=3^{n-1} $, then the first 5 terms are \begin{array}{l} a_1=3^{1-1}\\ a_1=3^{0}\\ a_1=1 ,\\\\ a_2=3^{2-1}\\ a_2=3^{1}\\ a_2=3 ,\\\\ a_3=3^{3-1}\\ a_3=3^{2}\\ a_3=9 ,\\\\ a_4=3^{4-1}\\ a_4=3^{3}\\ a_4=27 ,\\\\ a_5=3^{5-1}\\ a_5=3^{4}\\ a_5=81 .\end{array} Hence, the first 5 terms are $ \left\{ 1,3,9,27,81 \right\} $.
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