Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Sections 11.1-11.3 - Integrated Review - Sequences and Series - Page 653: 12

Answer

$\left\{ -12, -2,8,18,28 \right\} $

Work Step by Step

With $a_1=-12$ and $d=10$, then \begin{array}{l} a_{1}=-12 ,\\\\ a_2=a_1+d\\ a_2=-12+10\\ a_2=-2 ,\\\\ a_3=a_2+d\\ a_3=-2+10\\ a_3=8 ,\\\\ a_4=a_3+D\\ a_4=8+10\\ a_4=18 ,\\\\ a_5=a_4+d\\ a_5=18+10\\ a_5=28 .\end{array} Hence, the first 5 terms are $ \left\{ -12, -2,8,18,28 \right\} .$
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