Answer
$98$
Work Step by Step
The expression $
\displaystyle\sum_{i=1}^7 (3i+2)
$ evaluates to
\begin{array}{l}
(3\cdot1+2)+(3\cdot2+2)+(3\cdot3+2)+(3\cdot4+2)+\\(3\cdot5+2)+(3\cdot6+2)+(3\cdot7+2)
\\=
5+8+11+14+17+20+23
\\=
98
.\end{array}