Answer
$a_{7}=\dfrac{3}{32}$
Work Step by Step
Using $a_n=a_1r^{n-1}$, then
\begin{array}{l}
a_{7}=6\left( -\dfrac{1}{2} \right)^{7-1}\\\\
a_{7}=6\left( \dfrac{1}{64} \right)\\\\
a_{7}=\dfrac{3}{32}
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 11 - Sections 11.1-11.3 - Integrated Review - Sequences and Series - Page 653: 15
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