Answer
$\left\{
\dfrac{7}{2},\dfrac{7}{3}, \dfrac{7}{4}, \dfrac{7}{5},\dfrac{7}{6}
\right\}$
Work Step by Step
Given that $
a_n=\dfrac{7}{1+n}
$, then the first 5 terms are
\begin{array}{l}
a_1=\dfrac{7}{1+1}\\
a_1=\dfrac{7}{2}
,\\\\
a_2=\dfrac{7}{1+2}\\
a_2=\dfrac{7}{3}
,\\\\
a_3=\dfrac{7}{1+3}\\
a_3=\dfrac{7}{4}
,\\\\
a_4=\dfrac{7}{1+4}\\
a_4=\dfrac{7}{5}
,\\\\
a_5=\dfrac{7}{1+5}\\
a_5=\dfrac{7}{6}
.\end{array}
Hence, the first 5 terms are $
\left\{
\dfrac{7}{2},\dfrac{7}{3}, \dfrac{7}{4}, \dfrac{7}{5},\dfrac{7}{6}
\right\}
$.
