Answer
$a_6=64$
Work Step by Step
Substituting $n=6$ in $(-2)^n$, then,
\begin{array}{l}
a_6=(-2)^6\\
a_6=64
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 11 - Sections 11.1-11.3 - Integrated Review - Sequences and Series - Page 653: 5
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