Answer
$\left\{
-4,-1,4,11,20
\right\}
$
Work Step by Step
Given that $
a_n=n^2-5
$, then the first 5 terms are
\begin{array}{l}
a_1=(1)^2-5\\
a_1=1-5\\
a_1=-4
,\\\\
a_2=(2)^2-5\\
a_2=4-5\\
a_2=-1
,\\\\
a_3=(3)^2-5\\
a_3=9-5\\
a_3=4
,\\\\
a_4=(4)^2-5\\
a_4=16-5\\
a_4=11
,\\\\
a_5=(5)^2-5\\
a_5=25-5\\
a_5=20
.\end{array}
Hence, the first 5 terms are $
\left\{
-4,-1,4,11,20
\right\}
$.