Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 9

Answer

$y^2-y-6$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of $2$ binomials, the given expression, $ (y+2)(y-3) $, is equivalent to \begin{array}{l}\require{cancel} y(y)+y(-3)+2(y)+2(-3) \\\\= y^2-3y+2y-6 \\\\= y^2-y-6 .\end{array}
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