Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 28

Answer

$a^2-20a+100$

Work Step by Step

RECALL: $(a-b)^2=a^2-2ab+b^2$ Using the formula above with $a=a$ and $b=10$, the given expression is equivalent to: $=a^2-2(a)(10)+10^2 \\=a^2-20a+100$
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