Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set - Page 276: 18



Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of $2$ binomials, the given expression, $ (x^2+2)(x^2-8) $, is equivalent to \begin{array}{l}\require{cancel} x^2(x^2)+x^2(-8)+2(x^2)+2(-8) \\\\= x^4-8x^2+2x^2-16 \\\\= x^4-6x^2-16 .\end{array}
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