# Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set - Page 276: 6

$x^3-5x^2-6x+30$

#### Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of $2$ binomials, the given expression, $(x-5)(x^2-6)$, is equivalent to \begin{array}{l}\require{cancel} x(x^2)+x(-6)-5(x^2)-5(-6) \\\\= x^3-6x-5x^2+30 \\\\= x^3-5x^2-6x+30 .\end{array}

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