## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$x^2-0.01$
Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the given expression, $(x-0.1)(x+0.1)$, is equivalent to \begin{array}{l}\require{cancel} (x)^2-(0.1)^2 \\\\= x^2-0.01 .\end{array}