Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 17

Answer

$x^4-4x^2-21$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of $2$ binomials, the given expression, $ (x^2+3)(x^2-7) $, is equivalent to \begin{array}{l}\require{cancel} x^2(x^2)+x^2(-7)+3(x^2)+3(-7) \\\\= x^4-7x^2+3x^2-21 \\\\= x^4-4x^2-21 .\end{array}
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