Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 20

Answer

$q^2+\frac{3}{2}q+\frac{9}{16}$

Work Step by Step

RECALL: $(a+b)(a+b) = a^2+2ab+b^2$ Use the formula above with $a=q$ and $b=\frac{3}{4}$ to obtain: $(q+\frac{3}{4})(q+\frac{3}{4}) \\=q^2 +2(q)(\frac{3}{4})+(\frac{3}{4})^2 \\=q^2+\frac{3}{2}q+\frac{9}{16}$
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