Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 15

Answer

$15-13t+2t^2$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of $2$ binomials, the given expression, $ (3-2t)(5-t) $, is equivalent to \begin{array}{l}\require{cancel} 3(5)+3(-t)-2t(5)-2t(-t) \\\\= 15-3t-10t+2t^2 \\\\= 15-13t+2t^2 .\end{array}
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