# Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set - Page 276: 14

$16x^2-25$

#### Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of $2$ binomials, the given expression, $(4x-5)(4x+5)$, is equivalent to \begin{array}{l}\require{cancel} 4x(4x)+4x(5)-5(4x)-5(5) \\\\= 16x^2+20x-20x-25 \\\\= 16x^2+0x-25 \\\\= 16x^2-25 .\end{array}

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