Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 29

Answer

$x^2+20x+100$

Work Step by Step

RECALL: $(a+b)(a+b)=a^2+2ab+b^2$ Using the formula above with $a=x$ and $b=10$, the given expression is equivalent to: $=x^2+2(x)(10)+10^2 \\=x^2+20x+100$
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