Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Review Problem Set - Page 430: 5



Work Step by Step

Recall the following rule: $(\sqrt{x})^{2}=x$ Thus, we obtain: $-\sqrt \frac{4}{9}=-\sqrt \frac{2^{2}}{3^{2}}=-\frac{\sqrt {2^{2}}}{\sqrt {3^{2}}}=-\frac{2}{3}$
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